measurement in 3 Dimension

[Jarema]

Code:

# This 2.54 mean about centimeter. For DPI parameter use screen.physicalDpiX or screen.physicalDpiY.
def convert_pixels_to_cms(pixels, dpi):
            return (pixels / dpi) * 2.54

[quote Small Car Official Set 3177]
Source brickset.com/sets/3177-1/Small-Car
Minimum -45.00 -92.00 -90.00
Maximum 45.00 23.00 70.00
Perimeter 90x115x169
[/quote]

• First question is how translate length from Z axis to physical metric.
  
• Second question is when you have LDU how get width and height in physical metric.
  
• I know about LDCalc but we work in this scenario with 3D without scaling and without transformation.
  

[Roland Melkert]

I'm not entirely sure what you mean, but here's my 2cts

First question is how translate length from Z axis to physical metric.

You will need a bounding box of the 3D data you want to measure.

Second question is when you have LDU how get width and height in physical metric.

Divide it by 2.5 (don't confuse this with mm2inch which divides again by a similar 2.54).

[Max Martin Richter]

In my eyes the only thing you need, is to know, that 0.4 mm is 1 LDU. Followed by some calculations it should be easy to get the dimensions.

/Max

[Jarema]

Code:

Bounding Box:
  Minimum Point  -45.00 -92.00 -90.00
  Maximum Point 45.00  23.00  70.00
Perimeter of Box: 90x115x169

So, if this is correct:
X = 45.00 + 45.00 = 90.00
Y = 92.00 + 23.00 = 115.00
Z = 90.00 + 70.00 = 160.00

90 LDU * 0.4 mm = 36mm = 3,6 cm
115.00 LDU * 0.4 mm = 46 mm = 4,6 cm
160.00 LDU * 0.4 mm= 64 mm = 6,4 cm